3x^2+10=x^2=23x-20

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Solution for 3x^2+10=x^2=23x-20 equation: 



3x^2+10=x^2=23x-20

We move all terms to the left:

3x^2+10-(x^2)=0

We add all the numbers together, and all the variables

2x^2+10=0

a = 2; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·2·10
Δ = -80
Delta is less than zero, so there is no solution for the equation

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